⚛️ Unit 5 – Part A (2-Mark Q&A)

Engineering Physics

⬅ Back to Unit 5

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Part A: Semiconductor Physics

1) Direct vs Indirect bandgap semiconductors

Eg = Ec − Ev (direct: vertical in E–k).

2) Drift current vs Diffusion current

D/μ = kBT/q (Einstein relation).

3) Schottky diode vs Ohmic contact

I = IS(e^{qV/ηkT} − 1)

4) Hall effect & Hall voltage

Current I along x, magnetic field B along z ⇒ transverse voltage along y due to Lorentz force. Used to find type (n/p), carrier density, and mobility.

VH = (RH I B)/t, RH = 1/(q n) (n-type ⇒ negative sign), μ = σRH.

5) Why prefer extrinsic over intrinsic?

Extrinsic (doped) semiconductors provide much higher, controllable conductivity by adding donors/acceptors; enable n/p regions for diodes, BJTs, MOSFETs. Intrinsic has low σ and strong T-dependence.

σ = q(nμn + pμp)

6) Intrinsic vs Extrinsic semiconductor

AspectIntrinsicExtrinsic
PurityPure; n = p = niDoped (donor/acceptor)
Fermi levelMid-gapTowards CB (n) / VB (p)
ConductivityLow, T-sensitiveHigh, engineered
ExamplesPure Si, Gen-Si (P), p-Si (B)

7) Hole concentration in p-type (valence band)

For full ionization and light doping: p ≈ NA.

General (from F-D stats): p = Nv exp\{−(EF − Ev)/(kBT)\}

Mass-action law: np = ni2.

8) Given an extrinsic sample — identify n-type or p-type

Use Hall effect: measure polarity of Hall voltage.

Optional cross-checks: Seebeck sign, hot-probe test.

9) Energy band diagram of intrinsic semiconductor (T > 0 K)

  1. Valence band (VB) filled; conduction band (CB) nearly empty.
  2. Forbidden gap Eg = Ec − Ev.
  3. Equal electron–hole pairs thermally generated (n = p = ni).
  4. Fermi level at mid-gap: EF ≈ (Ec + Ev)/2.

10) Elemental vs Compound semiconductors (with examples)

Advantages of compounds: high electron mobility, direct Eg, lattice/ band-engineering (heterostructures).

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