🔬 Unit 2 – Part A (2-Mark Q&A)

24PY112 Engineering Physics

⬅ Back to Unit 2

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Part A: Oscillations, Acoustics & Thermal Physics

1) Torsional pendulum

A rigid body (disc/rod) suspended by a thin wire. Small twist → restoring torque by wire → angular SHM.

τ = −C θ (C: torsion constant), I d²θ/dt² + C θ = 0, period T = 2π√(I/C).

2) Travelling vs Standing waves (energy)

Standing wave formed by superposition of two opposite travelling waves of same f, A.

3) Weber–Fechner law

Perceived sensation is proportional to log of stimulus intensity:

S = k log(I/I₀) (I₀: threshold).

4) Doppler effect (sound)

Apparent frequency changes due to relative motion of source/observer.

f' = f \frac{v \pm v_o}{v \mp v_s} (signs: approach ↑, recede ↓); v is speed of sound.

5) Four sound-absorbing materials

6) Classification by frequency

7) Properties of ultrasonics

8) Magnetostriction & ultrasound production

Ferromagnets (Ni/Fe/Co) change length in a magnetic field. A rod in a coil with high-frequency AC experiences rapid elongation/contraction → emits ultrasonic waves.

Resonance when drive f matches rod’s natural longitudinal mode.

9) Three applications of ultrasonics

10) Bimetallic strip & use

Two bonded metals with different thermal expansion. Heating bends strip toward lower-expansion metal.

Used in thermostats, circuit breakers, dial thermometers.

11) Coefficient of thermal conductivity (k)

Rate of heat flow per unit area for unit temperature gradient (normal to area).

Q̇ = −k A (dT/dx); SI unit: W m⁻¹ K⁻¹.

12) Why roofs are painted white in summer?

White has high reflectance & low absorptance → less solar heat gain → cooler building & reduced AC load.

13) Thermal behavior of Invar

Fe–Ni alloy (~64% Fe, ~36% Ni) with very low CTE near room temperature → minimal expansion; used in precision instruments, clock pendulums, gauge blocks.

14) Seebeck effect

Temperature difference between junctions of two dissimilar conductors produces an EMF → continuous current in closed circuit. Basis of thermocouples.

Seebeck coefficient: S = ΔV/ΔT.

15) Heat conducted through a slab (numerical)

Given: A = 90×10⁻⁴ m², d = 1.2×10⁻³ m, ΔT = 20 K, k = 0.04 W m⁻¹ K⁻¹, Δt = 1 s.

Fourier: Q = kA(ΔT/d)Δt = 0.04×0.009×(20/1.2×10⁻³)×1 = 6 J.

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