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| cx2 + 2x | , x < 2 |
| x3 - cx | , x ≥ 2 |
Step 1: Set the Left-Hand Limit (LHL) equal to the Right-Hand Limit (RHL) at x=2
limx→2- (cx2 + 2x) = limx→2+ (x3 - cx)
Step 2: Substitute x=2 into both expressions:
c(2)2 + 2(2) = (2)3 - c(2)
4c + 4 = 8 - 2c
Step 3: Solve the linear equation for c:
6c = 4
c = 4/6 = 2/3
Step 1 (Domain): Identify that f(x) is a polynomial, defined for all real numbers.
Domain: (-∞, ∞)
Step 2 (Range): Identify that x2 is always non-negative.
Range: [0, ∞)
Step 3 (Graph): Sketch a parabola opening upward with its vertex at (0, 0).
Step 1: Set the denominator equal to zero to find restricted values:
x2 + x - 6 = 0
Step 2: Factor the quadratic equation:
(x + 3)(x - 2) = 0
Step 3: Solve for x to find the values excluded from the domain:
x = -3 and x = 2
Step 4: State the domain as all real numbers except the excluded values:
Domain: (-∞, -3) U (-3, 2) U (2, ∞)
Step 1: Use direct substitution of x=1 into the numerator and denominator:
Numerator: (1)2 - 4(1) = 1 - 4 = -3
Denominator: (1)2 - 3(1) - 4 = 1 - 3 - 4 = -6
Step 2: Calculate the limit:
limx→1 ... = (-3) / (-6) = 1/2
Step 1: Use direct substitution of x=5 (since it's a polynomial):
limx→5 (2x2 - 3x + 4) = 2(5)2 - 3(5) + 4
Step 2: Calculate the value:
2(25) - 15 + 4 = 50 - 15 + 4 = 39
Step 1: Set the radicand (expression inside the root) of the first term ≥ 0:
3 - x ≥ 0 ⇒ x ≤ 3
Step 2: Set the radicand of the second term ≥ 0:
2 + x ≥ 0 ⇒ x ≥ -2
Step 3: Find the intersection of the two inequalities:
-2 ≤ x ≤ 3
Domain: [-2, 3]
Step 1: Differentiate both sides with respect to x using implicit differentiation.
Step 2: Apply the Product Rule to d/dx(xy)
-sin(xy) · d/dx(xy) = 0 + cos(y) · dy/dx
-sin(xy) · (y + x(dy/dx)) = cos(y)(dy/dx)
Step 3: Distribute and isolate terms with dy/dx on one side:
-y sin(xy) = x sin(xy)(dy/dx) + cos(y)(dy/dx)
Step 4: Factor out dy/dx and solve:
dy/dx = (-y sin(xy)) / (x sin(xy) + cos(y))
Step 1: Find dy/dx using the Quotient Rule and simplify the numerator:
dy/dx = [(sec x tan x)(1 + tan x) - sec x(sec2x)] / (1 + tan x)2
dy/dx = [sec x (tan x - 1)] / (1 + tan x)2
Step 2: Set the numerator to zero (for a horizontal tangent):
sec x (tan x - 1) = 0
Step 3: Solve for x:
sec x = 0 (No solution)
tan x - 1 = 0 ⇒ tan x = 1
Step 4: State the general solution for tan x = 1:
x = π/4 + nπ, where n is an integer.
| 1 - x2 | , x ≤ 1 |
| log x | , x ≥ 1 |
Step 1: Calculate the Left-Hand Limit (LHL) at x=1:
limx→1- (1 - x2) = 1 - (1)2 = 0
Step 2: Calculate the Right-Hand Limit (RHL) at x=1:
limx→1+ (log x) = log(1) = 0
Step 3: Calculate the function value f(1):
f(1) = 1 - (1)2 = 0
Step 4: Conclude continuity since LHL = RHL = f(1)
0 = 0 = 0
The function is continuous.
Step 1: Find the first derivative f'(x):
f'(x) = 15x2 - 6
Step 2: Set the derivative equal to zero:
15x2 - 6 = 0
Step 3: Solve for x:
15x2 = 6
x2 = 6/15 = 2/5
x = ±√(2/5)
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